A liquid drop having surface energy E is spread into 512 droplets of same size. The final surface energy of the droplets is
Text Solution
Verified by ExpertsThe correct answer is:
C
The surface area of the liquid drop is A = 4 
R 2
Its surface energy is E
When the drop splits in 512 droplets, the surface area of each droplet is 4 
r 2
Total surface area A 2 = 512 x 4 
r 2
The volume of bigger drop is 
and volume of small droplets is 
Surface energy E = A. T (T is surface tension and A is area)
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